The printed global strict inequality needs a local correction. The formalization proves the weak global inequality, the exact region of strictness, and the downstream Laplace conclusions without assuming the false global strict form.
Source: Kleinberg and Raghavan, Algorithmic Monoculture and Social Welfare, Appendix C Definition 4 and Lemma 1.
Appendix C Definition 4 defines a noise kernel to be strictly well-ordered by a pointwise product inequality for four ordered score locations. Appendix C Lemma 1 then states that both Gaussian and Laplacian noise are strictly well-ordered.
The Gaussian strict statement is proved in Lean.
For the Laplacian kernel, the global strict statement is not true as a pointwise statement over all ordered quadruples.
Lean proves the globally valid weak Laplacian statement:
For every nonnegative Laplace rate lambda, the Laplacian
density kernel satisfies the weak well-ordering inequality.
Lean also proves strict Laplacian well-ordering on the overlap/local
region. Concretely, for ordered locations a > b and
c > d, the extra condition is
b < c and d < a.
Equivalently, the open intervals (b,a) and
(d,c) overlap. That is the strictness condition available
from the analytic inequality itself.
The downstream Laplace route does not require the false global strict form. It uses the weak comparison for the density-swap step, and strict payoff improvement comes from later support and monotonicity facts. No named theorem or main-text result is affected.
The overlap condition is not stated elsewhere in the paper’s
Definition 4, Lemma 1, Theorem 6, or Lemma 3 source text. Those passages
use the global wording “for any a > b and
c > d.”
Lean therefore does not prove the downstream Laplace result by treating the overlap theorem as a global replacement for Definition 4. Instead, the formalization takes a different valid route for Laplacian noise:
Using the unnormalized Laplacian kernel
f_x(y) = exp(-lambda * |y - x|)
take lambda = 1 and the all-positive ordered
locations
a = 11, b = 10, c = 2, d = 1.
The global strict claim would require a strict inequality between the two products appearing in Definition 4. But both sides are equal:
f_a(c) * f_b(d)
= exp(-|2 - 11|) * exp(-|1 - 10|)
= exp(-9) * exp(-9)
= exp(-18),
and
f_a(d) * f_b(c)
= exp(-|1 - 11|) * exp(-|2 - 10|)
= exp(-10) * exp(-8)
= exp(-18).
So the strict inequality fails even with a,
b, c, and d all strictly
positive. The correct global statement is weak inequality; strictness
requires the overlap/local condition b < c and
d < a, not positivity. In this example, the condition
fails because b = 10 and c = 2, so the two
intervals are separated.